What is the product of the following reaction?

An organic compound $(A)$ (molecular formula $C_{8}H_{16}O_{2}$) was hydrolysed with dilute sulphuric acid to give a carboxylic acid $(B)$ and an alcohol $(C)$. Oxidation of $(C)$ with chromic acid produced $(B)$. $(C)$ on dehydration gives but$-1-$ene. Write equations for the reactions involved.

Hence the product $(Y)$ in the above sequence of reactions,is

The increasing order of acidity of the following carboxylic acids is:

Match List-$I$ and List-$II$.

List-$I$	List-$II$
$(a)$ $R-COCl \to R-CHO$	$(i)$ $Br_2 / NaOH$
$(b)$ $R-CH_2-COOH \to R-CH(Cl)-COOH$	$(ii)$ $H_2 / Pd-BaSO_4$
$(c)$ $R-CONH_2 \to R-NH_2$	$(iii)$ $Zn(Hg) / \text{Conc. } HCl$
$(d)$ $R-CO-CH_3 \to R-CH_2-CH_3$	$(iv)$ $Cl_2 / \text{Red } P, H_2O$

Choose the correct answer from the options given below:

In Column-$I$ formula,in Column-$II$ general name and in Column-$III$ $IUPAC$ name are given. Match the items in Column-$I$ with the appropriate items in Column-$II$ and Column-$III$.

Column-$I$ (Formula)	Column-$II$ (General Name) and Column-$III$ ($IUPAC$ Name)
$(A)$ $HCOOH$	$(i)$ Succinic acid,$(x)$ Methanoic acid
$(B)$ $CH_3CH_2CH_2COOH$	$(ii)$ Oxalic acid,$(y)$ Ethanedioic acid
$(C)$ $(COOH)_2$	$(iii)$ Formic acid,$(m)$ Butanedioic acid
$(D)$ $(CH_2)_2(COOH)_2$	$(iv)$ Butyric acid,$(n)$ Butanoic acid